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6x+2x^2=-2x^2-10
We move all terms to the left:
6x+2x^2-(-2x^2-10)=0
We get rid of parentheses
2x^2+2x^2+6x+10=0
We add all the numbers together, and all the variables
4x^2+6x+10=0
a = 4; b = 6; c = +10;
Δ = b2-4ac
Δ = 62-4·4·10
Δ = -124
Delta is less than zero, so there is no solution for the equation
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